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sql查询 次数

select Name as '姓名', count(base) as '咨询次数' from A inner join B on A.a = B.b where Date between '2015-06-15 00:00:00' and '2015-06-21 23:59:59' and qykf='签约客户' and Name in ('李雷','韩梅梅') group by Name order by Name;

select count(name) ,name from table group by name having count(name)>1

需要用group by中的having子句。 1、如test表中有如下数据: 2、现要查出dept出现2次以上的dept。可用如下语句: select dept from test group by dept having count(*) >2;3、查询结果:

我觉得好像不用楼上那么复杂吧? 1 select count(*) from (select distinct 列名 from 表名) 子查询中使用distinct查询出所有不同的值,然后用select count(*)查询子查询返回到行数。

使用count函数即可。 例如: 表名test id name 1 a 1 b 1 f 2 c 2 d 3 e select id from test group by id having count(*)=(select top1 count(*) as counts from test group by id order by counts desc)

select top 1 pid, count(pid) as [pidcount] from 表名 group by pid order by pidcount desc 如果只要pid,可以 select pid from (select top 1 pid, count(pid) as [pidcount] from 表名 group by pid order by pidcount desc) as a

一条SQL语句就可以了,假设这个表名是table1 select count(*) as bbb from table1 where name='张三' 得到的表只有一个字段一行记录,字段名就是bbb,唯一记录中的bbb值就是统计的次数

SELECT [字段],COUNT(0) AS 重复次数 FROM [表名] GROUP BY [字段] HAVING COUNT([字段]) > 1

--查询指定条件下的重复次数--测试数据with tabname(id,name) as (select 1,'name1' union allselect 1,'name1' union allselect 1,'name1' union allselect 1,'name2' union allselect 1,'name2' union allselect 1,'name3' union allselect 2,...

select 字段,count(*) from 表明 group by 字段

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