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sql查询 次数

select Name as '姓名', count(base) as '咨询次数' from A inner join B on A.a = B.b where Date between '2015-06-15 00:00:00' and '2015-06-21 23:59:59' and qykf='签约客户' and Name in ('李雷','韩梅梅') group by Name order by Name;

我觉得好像不用楼上那么复杂吧? 1 select count(*) from (select distinct 列名 from 表名) 子查询中使用distinct查询出所有不同的值,然后用select count(*)查询子查询返回到行数。

select count(name) ,name from table group by name having count(name)>1

select 字段,count(*) from 表明 group by 字段

select B, count(*) -- 计算个数,速度快于count(字段). 因为 count(字段)会先判断这个字段是否为空,只计算非空的个数。所以这里直接用count(*)。 from A group by B

特别推荐: select xingming , count(*) from biao group by xingming having count(*) > 2

使用group进行分组来实现。 例句: select a,count(*) from table group a ; 显示的结果,a就是重复的值,count(*)就是重复的次数。 该SQL在Oracle、Sql Server等数据库都适用。 若要筛选重复几次的重复值,则可对sql进行变动。 比如要显示重...

使用count函数即可。 例如: 表名test id name 1 a 1 b 1 f 2 c 2 d 3 e select id from test group by id having count(*)=(select top1 count(*) as counts from test group by id order by counts desc)

select playerid,count(*) from userlogin group by playerid having count(*)>10

sql 计算重复数据个数 可以使用 count 来统计 例子 personal表 id name 1 xm 2 xm 3 mx 统计personal表中name为xm的个数 select count(name) total from personal where name='xm' 结果 total 2

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