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sql查询 次数

select count(name) ,name from table group by name having count(name)>1

需要用group by中的having子句。 1、如test表中有如下数据: 2、现要查出dept出现2次以上的dept。可用如下语句: select dept from test group by dept having count(*) >2;3、查询结果:

我觉得好像不用楼上那么复杂吧? 1 select count(*) from (select distinct 列名 from 表名) 子查询中使用distinct查询出所有不同的值,然后用select count(*)查询子查询返回到行数。

SELECT 某列, COUNT(*) FROM 某表 GROUP BY 某列 ORDER BY COUNT(*)

select Name as '姓名', count(base) as '咨询次数' from A inner join B on A.a = B.b where Date between '2015-06-15 00:00:00' and '2015-06-21 23:59:59' and qykf='签约客户' and Name in ('李雷','韩梅梅') group by Name order by Name;

select a.duiwu ,a.胜,b.负 from (select count(*) 胜, duiwu from tabb where shengfu='胜' group by duiwu ) a left join (select count(*) 负, duiwu from tabb where shengfu='负' group by duiwu ) b on a.duiwu=b.duiwu --sql2000调试通过...

使用count函数即可。 例如: 表名test id name 1 a 1 b 1 f 2 c 2 d 3 e select id from test group by id having count(*)=(select top1 count(*) as counts from test group by id order by counts desc)

我觉得好像不用楼上那么复杂吧? select count(*) from (select distinct 列名 from 表名) 子查询中使用distinct查询出所有不同的值,然后用select count(*)查询子查询返回到行数。

你可以按年月来汇总 select left(CONVERT(varchar(10),[date],112),6) as 月份,sum(num) as 总次数 from table1 group by left(CONVERT(varchar(10),[date],112),6)

1、当日12~次日12点,可以把时间加上12个小时再计算,就是到次日12点再结算。 2、再根据处理后的日期group by。 3、获取group by以后的记录条数即可。 完整sql如下,在SqlServer2008下测试通过: select count(*) as '消费次数' from (select [...

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